\f\f* How to we RB: * How to we Ra : FOR # 2 CLUE TO SOLVE same method in Ra but Series Rg & Ra so that the uses Re 8 RB. outcome of there two resistors FIRST REDRAW R4 can be used to pair w / RJ AMAAA in parallel. R3 JI R4 Rq RIO + AAAA AAN J 2 3 J4 AMAA AMA O 02= RB = Ra = On 6 . J Ro AAAAAA JS Either Ra OR RB Ra is an imaginary Resistor RB is also has the w / a value of OR. same role of Ra. No impact in calculation but has an you can choose w/c to use. important role to balance the diagram NOTE: Pick 1 only as not to disrupt diagram