[re] 2 f3\" met" 6:3 am, what is Fr (x)? C) 11433? 61,3 e) O 0 11191195 13:2) 3)? 6(m 3)3 3) O 1n{3(37) 5(33) 3) 4. For the function F [551\") = If; Ina) (it, evaluate F 1(2). 0 23 111(2) 0 32 111(2) 0 1281n{2] 5. Find the derivative of the function mm) = 0 48:32 4 O 3:):2 O 192:3:'14 0 192m? 0 12:32 11. Using a trapezoidal approximation. with four enhintervals of equal size, approximate the area. between the graph of f and the x-exis on the interval [0, S 1. Estimate the area. under the curve f (at) = 51:2 2:1: 1 using a. midpoint Riemann 511111, with 3 rectangles, on the interval [2, 1] . 07 G? . 712 0% 012 10. The table below gives values of a continuous function f. On the interval [-7, 1], the trapezoidal approximation for the area under the function, found with 4 intervals of equal length, is 3. What is the value of k? 7 5 3 1 f Ex 8 0 k 0 9 O 19 10 O 1 28 14.518. Let f be the function defined by f (x) = Vz+ 31 Which of the following statements is true? O f is not differentiable at a = -3 O lim+ + 3 f (x) #0 O f is not continuous at a = -3 O = -3 is a vertical asymptote of the graph of f O f is continuous and differentiable at a = -3Graph of f 2 -2 2 6 -2 12. Given the graph of f shown above, which of the following statements is false? O f (5) =0 O lim+ +0- f (x) =1 O lim+-2 f (x) = 2 O f (2) = -2 O lim, +1- f (2) = -1 13. Let f be a function that is continuous on the closed interval [4, 16]. Given that f (4) = 6 and f (16) = 14, which of the following statements is guaranteed by the Intermediate Value Theorem? Of (x) = 10 has at least one solution in the open interval (4, 16) There is at least one maximum on the open interval (4, 16) O f (x) is always increasing O f (x) is linear O f (10) = 1014. Use a left and right Riemann Sum to approximate the area under this curve on the interval [ 4, 4] . Graph of f ply-l Which gives an underestimate? Overestimate? 0 Left is an underestimate, right is an overestimate. 0 It depends on the size of the rectangles used. 0 Both are overestimates. 0 Both are underestimates. O Left. is an overestimate, right is an underestimate. 15. Using a midpoint Riemann sum. with 4 rectangles of equal width, 51:3323 and the 1' - T xaxis on the interval {-23}. For any Intervals on which the function dips below the xaxis, count the area as negative. 0 A = 2.33? estimate the area between the function f (33} = O A = 4.137 O A = 5.212 O A = 3.006 O A = 5.334