ffSolve the initial value problem. JI 2 = - 3 csc = 0;y = 2 dx The
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\f\fSolve the initial value problem. JI 2 = - 3 csc = 0;y = 2 dx The solution is y = (Type an exact answer, using it as needed.)If1 Evaluate the integral J 2ms 5t sin 5t dt. 0 If1 I 2mm\"t sin 51m = D U [Type an exact answer.) \f\f