\fI SOLVING EQUATIONS AND FACTORING SOLVE FOR 4 IN SIMPLEST FORM : O xy' + y = 1+ y' 2 3 x yy' + 2 xya = a yy' SOLVE. ( USE FACTORING , COMPLETING THE SQUARE , OR THE QUADRATIC FORMULA. ) 3 4x2 - 21x - 18= 0 2x2 - 3 x + 3 = 0 5 X4 - 9x +8 : 0 FACTOR COMPLETELY. (LEAVE NO FRACTIONAL OR NEGATIVE EXPONENTS.) 6 3x3 + 192 @ 9x2-3x - 2 1 2 V X - 6X 3/2sin x + Lan x 1 e-xe +axe @ 2x"+5x3- 3 x2 VI. EQUATIONS OF LINES O. FIND THE EQUATION OF THE LINE THAT PASSES THROUGH THE POINT ( 2:4 ) . AND IS PARALLEL TO THE LINE 2 x + 3 4 - 8 : 0 FIND THE EQUATION OF THE LINE THAT IS PERPENDICULAR TO THE LINE 2 x + 4 : 5 AT THE : POINT ( 1, 2 ) THE LINE WITH SLOPE 5 THAT PASSES THROUGH THE POINT (- 1, 3 ) : INTERSECTS THE X- AXIS AT WHAT POINT??(4) WHAT ARE THE COORDINATES OF THE POINT AT WHICH THE LINE PASSING THROUGH THE POINTS ( 1 , - 3 ) AND ! ( -2:4) INTERSECTS THE '4-AXIS ? . . . CONSIDER THE FUNCTION :f(x) =X3- X. a IS THE POINT ( 3, 2 ) ON THE GRAPH ? (b) IS THE POINT (2. 6 ) : ON THE GRAPH ? FIND THE X AND y - INTERCEPTS.\fVIII . DOMAIN USE INTERVAL NOTATION TO IDENTIFY THE DOMAIN OF EACH FUNCTION : K ( x ) = ly2 - 5x - 14 4x2 - 21 x- 18 3 f ( x ) = V X - 6 @ d ( x )= In (2x-12) X? - X - 30 IX. GRAPHING FUNCTIONS GRAPH EACH . FUNCTION : 2 x (-00 , - 1 ) 2 x 2 [- 1, 2) y = x 2 - 4x + 3 f ( x ) = - X +3 [2, 00) . .. . .3 f ( x ) = V16- x2 @ y= x-2 +3 X. FUNCTIONS O GIVEN THAT f ( x ) = 1x- 3 -5 . FIND f ( 1 ) - f ( 5 ) . 2 GIVEN THAT 9 (x ) = X2 - 3x+4 , FIND 9 ( x +2 ) - g ( 2 ). 3 IF f ( x) = 8x2+1 , FIND f ( xth ) - f ( x ) h 4 GIVEN f ( x ) = X - 3 AND 9 ( x ) = UX , FIND : @ f( g ( x) ) 6 9 (f(x)) @ f ( f ( x ) )