Field and force with three charges At a particular moment, one negative and two positive charges are located as shown in the figure. Your answers to each part of this problem should be vectors. It helps a great deal to make a diagram with arrows representing the various electric field contributions, and then check the signs of your components against these arrows. Let Q1 = 3 HC, Q2 = 7 HC, and Q3 = -5 HC. 1 cm Q3 (a) Find the electric field at the location of Q1, due to Q2 and Q3. E = N/C (b) Use the electric field you calculated in part (a) to find the force on Q1. F = (c) Find the electric field at location A, due to all three charges. E N/C (d) An alpha particle (He2+, containing two protons and two neutrons) is released from rest at location A. Use your answer from part (c) to determine the initial acceleration of the alpha particle. (Use 6.646 x 10-27 kg for the mass of He 2+ . ) a m/s25. [-/2 Points] DETAILS M14 13.6.XP.008. MY NOTES PRACTICE ANOTHER The distance between the dipole and the point charge in the diagram in the figure is d. If the distance between them were changed to 0.1*d, by what factor would the force on the point charge due to the dipole change? (new force / old force) = Edipole +9+ -q te d > >s Additional Materials eBookTwo dipoles are oriented as shown in the diagram below. Each dipole consists of two charges +q and -q, held apart by a rod of length s, and the center of each dipole is a distance d from location A. If q = 4 nC, s = 1 mm, and d = 7 cm, what is the electric field at location A? Hint: draw a diagram and show the direction of each dipole's contribution to the electric field on the diagram (you do not have to turn in the diagram). AX E = V/C