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The following scatterplot shows the mean annual carbon dioxide (CO2 ) in parts per million (ppm) measured at the top of a mountain a) What

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The following scatterplot shows the mean annual carbon dioxide (CO2 ) in parts per million (ppm) measured at the top of a mountain a) What is the correlation between CO2 and Temperature? and the mean annual air temperature over both land and sea across the globe, in degrees Celsius (C). Complete parts a through h on the right. r= 16.800 (Round to three decimal places as needed.) 16.725 b) Explain the meaning of R-squared in this context. Mean Temperature (C 2 16.650 O A. A linear model on mean temperature accounts for 33.8% of the variation in CO2 levels. 16.57 O B. A linear model on CO2 levels accounts for 33.8% of the variation in mean temperature. 16.500 325.0 337.5 O C. A linear model on mean temperature accounts for 66.2% of the variation in CO2 levels. CO2 (ppm) 350.0 362.5 Click here to view the regression output. O D. A linear model on CO2 levels accounts for 66.2% of the variation in mean temperature. Click here to view the residual plot. c) Give the regression equation. Using the provided regression output, the equation is Temp =+co2. (Type integers or decimals. Do not round.) d) What is the meaning of the slope of this equation? O A. For every 0.003 ppm increase in CO2 levels, the mean temperature increases by 1 C. O B. For every 1 ppm increase in CO2 levels, the mean temperature increases by 0.003 C. O C. For every degree that the mean temperature increases, CO2 levels increase by 0.003 ppm. O D. The slope does not have a meaningful interpretation in the context of this problem. e) What is the meaning of the y-intercept of this equation? O A. For every 1 ppm increase in CO2 levels, the mean temperature increases by 0.003 C. O B. When the CO2 level is 0 ppm, the global mean temperature will be 15.606 C. O C. When the global mean temperature is 0 C, the CO2 level is 15.606 ppm. O D. The y-intercept does not have a meaningful interpretation in the context of this problem.The following scatterplot shows the mean annual carbon dioxide (C02) in parts per million (ppm) measured at the top of a mountain and the mean annual air temperature over both land and sea across the globe, in degrees Celsius (C). Complete parts a through h on the right. A I . a 10.300 . 2 c ' a 16725 . o ' ' s - - ' 5.16630 I ' E ' . n: o 15575 . - . . '2 u 3 16 500 E 3150 75 3500 szs COZWDW) Click here to view the regression outpuit. Click here to view the residual PM u v. rul cvcly uegm: mm ulc mean lclllpclululc Illulcuaca, uuz Icvcla Illulcunc uy u.uw ppm. 0 D. The slope does not have a meaningful interpretation in the context of this problem. e) What is the meaning of the yintercept of this equation? 0 A. For every 1 ppm incnease in (:02 levels, the mean temperature increases by EI.003C. O B. When the CO2 level is 0 ppm, the global mean temperature will be 15.606C. O c. When the global mean temperature is 0C, the CO2 level is 15.606 ppm. 0 D. The yinteroept does not have a meaningful interpretation in the context of this problem. f) Wew the accompanying scatterplot of the residuals vs. 002. Does the scatterplot of the residuals vs. CO2 show evidence of the violation of any assumptions behind the regnession? O A. Ya, the outlier condition is violated. O B. No, all assumptions are okay. 0 C. Ya, all the assumptions are violated. O D. Yes, the linearity assumption is violated. O E. Ya, the equal variance assumption is violated. O F. YE, the linearity and equal variance assumptions are violated. 9) Suppose CO2 levels reach 362 ppm this year. What mean temperature does the regression pnedict from this information? n C (Round to three decimal places as needed.) h) Does the answer is part 9 mean that when CO2 levels hit 362 ppm, the temperature will neach the predicted level? Explain briey. O A. No. The actual temperature will be signicantly higher than the predicted level. 0 B. No. The actual temperature will be 15.6D6C. O C. Ya. The temperature will reach the predicted level when CO2 levels hit 362 ppm. 0 D. No. The actual temperature is likely to be ditferent than the predicted level

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