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Find all the critical points and the Inflection points. -2??x?2? cos (2x y = 3 - 2 sin- 8 cos ( 274) (cos ( 201)

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Find all the critical points and the Inflection points. -2??x?2?

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cos (2x y = 3 - 2 sin- 8 cos ( 274) (cos ( 201) +2) + 16 sin (210) (1 05( 22)+2) 8/ cos ( 271) 1los (274) +2 ) - 2 sin? ( 270) ( cos ( 274 + 2 ) - 8 [ cos' ( 2X1 ) + 2 cos ( 221) - 2 ( 1 - cos] ( 2x ) ) ] (cos ( 2 21 ) + 2 ) 3 0- - 8 [ 3 cos ? ( 271 ) + 2 cos (2x1) -2] cos ( 27) + 2 13 10 2 3 cos ( 27) + 2 ros ( 270 ) - 2 - 2 I / 4+ 24 6 -2+ 28 6 3 271 = 0.549 + 2 An und - 1.215 + 2 An 1= 0.274 + 7in and - 0. 608 + TinOur and derivative is, daz = - 8 ( 27 Cos2 24) coszx - 16 sin2(2x) ( 2+ ROD 2x ) ( 2+ @vx 2 x ) 4 - 8 ( 2 + co) 2 x ) Co8 2x - 16 sin ( 2 21 ) ( 2+ eos 2 x ) 3 - 8 [ 2 eos201 + Cos 220 + 2 Sin 2 2 21/ won ( 2+ Cor> 2 2( ) 3 - 8 ( 2 8012 2 + Cox 2x + 28 2 CoxV 2x ( 2+ (082 21) 3 ( 2+ 2 eosin - cost20) - 8 13 - ( 1- 2 evs2 2 + Cos 2x) ( 21 Cos 2 20 ) 3 = - 8 _3 - ( 1 - cox x ) ( 2+ Cos 220 )3 - - 8 13 - ( 2 sin ax ) ] ( 2 + Cors 2 21) 3 - 8 ( 3 - 4 singEx ) ( 20 Co) 2 x ) 3 NOW 2 2 JM 2 - 8 ( 3 - 4 sin4x) ( 2+ CUR 2x ) 3 -4 sing = 0 sing = 3 sing ( 3 ) re = sin (( 3 ju Then in the interval -20 5 x 4 271- 271 + sint (2) 9 , - TV + sin' [ ( 9 ) 4] - T- sings (= ) 97 where sins ( 2)2 1 = 1. 19606

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