Find an equation for the line tangent to the curve at the point defined by the given value of t. Also, find the value of - day dy2 at this point. x = sec t, y= cos t; t= - Write the equation of the tangent line. y = _x +0 (Type exact answers, using radicals as needed.) ew an example Get more help Q Search ZenBook pause 12 break 10 F11 & O 2 3 W E R T Y P S F G H K X C V B N Man an = at [ using chain rule] da from First Part = *+ ( - cost ) . seelt ) tan ( t ) dro -- cost dt - du seelt)tant = - 2 costt) ( cost ).- seelt ) tam(t ) = - 2 cos(t ) ( - sim ( + ) ) - see(t) tan(t ) = 2co3 ( + ) sim(t ) . 1 sin(t ) coS( t ) Cos(t ) 2 2 cos ( t ) sinkt ) . cos ( t ) sin (t ) = 2 cos' ( t ) . 4t t = 1 /60 = 2 cos ( 7/6 ) - 2 . ( 13 ) - 3V3 x 2 ( 3) 3 3V3 dry at t= 4/6 is duz 3 V3