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Find me margin of error for the given mines of e, 5, and n. e=i].Bi], 5:11, n=9 g Click the icon In View the tdietributien

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Find me margin of error for the given "mines of e, 5, and n. e=i].Bi], 5:11, n=9 g Click the icon In View the tdietributien table. The margin af error is D. {Round to one decimal place as needed} Use the confidence interval to find the margin of error and the sample mean. (0.682,0.780) The margin of error is The sample mean isWhen a population is finite, the formula that determines the standard error of the mean needs to be adjusted. If N is the size of the population and n is the size of the sample (where n 2 0.05N), the standard error of the mean is shown below. The finite population correction factor is given by the expression (N -n) / (N -1). Determine the finite population correction factor for each of the following. (a) N = 1900 and n = 950 (b) N = 1900 and n = 190 (c) N = 1900 and n = 100 (d) N = 1900 and n = 95 (e) What happens to the finite population correction factor as the sample size n decreases but the population size N remains the same? (a) The finite population correction factor is (Round to three decimal places as needed.) (b) The finite population correction factor is (Round to three decimal places as needed.) (c) The finite population correction factor is (Round to three decimal places as needed.) (d) The finite population correction factor is (Round to three decimal places as needed.) (e) What happens to the finite population correction factor as the sample size n decreases but the population size N remains the same? O A. The finite population correction factor approaches 1. O B. The finite population correction factor does not approach any set value. O C. The finite population correction factor approaches 0. O D. The finite population correction factor approaches NI -1 # 0.707.Find the margin of error for the given values of c, 6, and n. c = 0.90, 6 = 2.9, n=36 E Click the icon to view a table of common critical values. E = Round to three decimal places as needed.)In a random sample of 9 cell phones, the mean full retail price was $513.90 and the standard deviation was $139.01]. Further research suggests that the population mean is $431.79. Does the tva ue for the original sample fall between 4099 and 10-99? Assume that the population oitull retail prices for cell phones is normally distrib uted. ( ..... The tvalue ott= D T fall between to_99 and tnsg because toss = Cl. (Round to two decimal places as needed.) Use the given eendenee interval to find the margin uf error and the sample mean. {13.3.1212} The sample mean is E. [Type an integer er a decimal} The margin of error is E. [Type an integer er a decimal}

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