Find the area of the shaded region. y = x 8 3y = 2x+ 16 (1, 6) 6/ 4 (2, 4) (-2, 4) 2 y =8 - 2X -4 X -2 2 4 A =Sketch the region enclosed by the given curves. Decide whether ti) integrate with respect ti) )1 or y. Draw a typical approximating rectang'e. Find the area of the region. Sketch the region enclosed by the given curves. y = 12 - x , y=x2 - 6 5 5/ 10 LX X -6 -2 4 6 -6 -4 2 -4 1-2 2 6 51 -5 -5 X -6 6 X -6 -4 -2 2 4 6 -10 -10 -5 O Find the area of the region.Sketch the region enclosed by the given curves. y = V5x, y = =x 4 4 4 2 2 2 -30 X -20 -10 X 10 20 30 -30 X -4 -20 -10 -2 2 10 4 20 30 -4 -2 2 -2 -2 -2 -4 -4 -4 -6 - 6 Find the area of the region.Sketch the region Enclosed by the given curves. y=Zcos(x), y=272cos(x), 05x57: Find the area of the region. Sketch the region enclosed by the given curves. y:. y:8X, y:%x, x>0 Find the area of the region. A graphing calculator is recommended. Use a graph to find approximate x-coordinates of the points of intersection of the given curves. Then find (approximately) the area of the region bounded by the curves. (Round your answer to two decimal places.) y = 5x sin(x ), y = 5x4, x 20 Need Help? Read It [-/2 Points] DETAILS SCALCET9 6.1.049. MY NOTES PRAC A computer algebra system is recommended. Graph the region between the curves. y = 1 + x4' y = 2x2 -2 2. O -5 Compute the area of the region. (Round your answer to five decimal places.)