Find the center, foci, and vertices of the ellipse. Graph the equation. 36x + 360x + 16y-96y +468 = 0 36 (x+ 10x) + 16 (-6y) = - 468 Use the complete the square process to convert the given ellipse to standard form 36 (x +10x) + 16 (y-6y) - Standard form: = - 468 The center of the ellipses is located at The distance to the vertices, a = The focal length, c = (Simplify if needed) The main avie of the allinea is narallel to the Lavie The value of b =