Find the curve's unit tangent vector. Also, find the length of the indicated portion of the curve. r(t) = 6ti+ 2t j-3t k 1sts2Find the curve's unit tangent vector. Also, find the length of the indicated portion of the curve. r(t) = (5t sin t + 5 cost)i + (5t cost - 5 sint)j :/2 sts2 The curve's unit tangent vector is ( cost ) i+ ( - sint )j + ( 0 ) k. The length of the indicated portion of the curve is units. (Simplify your answer.)Find the point on the curve r(t) = (5 sint)i + (-5 cost)j - 12tk at a distance 52x units along the curve from the point (0, -5,0) in the direction of increasing arc length. The point is D (Type exact answers, using x as needed.)Find the arc length parameter along the given curve from the point where t=0 by evaluating the integral s(1) = _ v(t)|dt. Then find the length of the indicated portion of the curve r(t) = 8costi + 8sint j + 5t k, where 0 Osts 4Find the arc length parameter along the curve from the point where t= 0 by evaluating the integral s = , lv|dt. 0 Then find the length of the indicated portion of the curve. r(t) = (4e cost)i+ (4e sint)j-4e k, - In4sts0)Find the arc length parameter along the curve from the point where t= 0 by evaluating the integral s = _ v(t)| dt. 0 Then find the length of the indicated portion of the curve. r(t) = (6 + 2t)i + (9 + 4t)j + (1 - 3t)k, - 1sts0