Find the general solution of the differentialequation below and check the result by differentiation.

$\frac{dQ}{dt}=\frac{8}{5}{t}^{\frac{3}{5}}$

$Q(t)=\frac{24}{25}{t}^{\frac{8}{5}}+C$

$Q(t)=t^{\frac{8}{5}}+C$

$Q(t)=\frac{8}{5}{t}^{\frac{8}{5}}+C$

$Q(t)=\frac{24}{25}{t}^{\frac{-2}{5}}+C$

$Q(t)=t^{\frac{8}{5}}$