Find the indefinite integral. (Use C for the constant of integration.) / 2 fu 16x2 + 25 X4 Find the indefinite integral. (Use C for the constant of integration.) 16x2 + 25 dx 25 25 + C 12x 3 4x XTo integrate ( v 102 42 da, you can use the substitution method. Let u = 16x2 + 25, then du = 32x dx. So, the integral becomes: Vu 7-3 au Now, rewrite a as x2 . x: Vu 1 - du 22 Substitute du = 32x da: 1 Vu I du 32 x 32x This simplifies to: 322 23 du Now, integrate / vy du with respect to u. This integral is of the form S um du, which has a solution of = u fu3/2 + C. So: 1 2, 3/2 + C 322 3 Finally, substitute back u = 16x- + 25: 1 322 . 3 (16x2 + 25)3/2 + C Thus, the indefinite integral of V16: +25 is 1 (16x2 + 25)3/2 + C