Question
FIND THE PERCENT DISCREPANCY (PERCENT ERROR) IN THE EXPERIMENTAL RESULT OF GRAVITATIONAL ACCELERATION.REPORT ALL THE EQUATIONS OF MOTION FOR EXPERIMENTS 1 AND 2 AND 3
FIND THE PERCENT DISCREPANCY (PERCENT ERROR) IN THE EXPERIMENTAL RESULT OF GRAVITATIONAL ACCELERATION.REPORT ALL THE EQUATIONS OF MOTION FOR EXPERIMENTS 1 AND 2 AND 3 IN THE TABLE BELOW.
TYPE OF MOTION:
POSITION-TIME EQUATION:
VELOCITY-TIME EQUATION:
experiment 2:
The position-time graph's coefficient "A" has a value of 0.142. The velocity-time graph's slope is 0.284. As of right now, the coefficient "A" value from the position-time graph is 0.142, or 0.284 / 2 (or 0.142). As a result, the slope of the velocity-time graph is equal to half of the value of coefficient "A" from the position-time graph. As well as For evenly accelerated linear motion, the equation of motion is At2 + Bt + C = x.
We obtain the following values for coefficients A, B, and C from table 2:
A = 0.142,B = 0.14, C = 0.145.
Consequently, the following is the equation of motion for the cart's evenly accelerated linear motion:
x = 0.142t2 + 0.14t + 0.145.
EXPERIMENTS 3
Value of g and its uncertainty:
Percent discrepancy:
gravitational acceleration:
Table 2 POSITION VS TIME GRAPH I A Value uncertainty B Value uncertainty C Value uncertainty Away from the 0.142 +/- 9.1 .140 +/- 8.7 .145 +/ 9.5 motion sensor Table 3 VELOCITY VS TIME GRAPH Run # Slope (velocity vs time y-intercept, (velocity vs time graph graph) Away from the motion sensor 0.284 +/- .0025 -0.300 +/ 0.0056 \fExperiment 1: Constant Velocity Motion Table 1 Way of Moving Slope (position vs time y-intercept (position vs time graph) graph Toward to the Motion Sensor ~0.285 +/- 0.0036 Experiment 2: Uniformly Accelerated Motion Table 2 POSITION VS TIME GRAPH A Value uncertainty B Value uncertainty C Value uncertainty Away from the 0.142 +f- 9.1 .140 +/- 8.7 .145 +;'- 9.5 motion sensorStep by Step Solution
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