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find the point on the curve y= x^5/2 for which the tangent line to the curve is perpendicular to the line 128x+3645y+345=0 Find the point

find the point on the curve y= x^5/2 for which the tangent line to the curve is perpendicular to the line 128x+3645y+345=0

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Find the point on the curve y = a/ for which the tangent line to the curve is perpendicular to the line 128x + 3, 645y + 345 = 0. Note: Write the exact answer but not the approximate value (For example write but not 0.8) Answer: The point is (x, y) where

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