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Find the real zeros of the function. (2x+2)28(2x+2)+15 X X= =-52.x=1/1 X x=-3x= - 31/12 X X = 1 X = > x =

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Find the real zeros of the function. (2x+2)28(2x+2)+15 X X= =-52.x=1/1 X x=-3x= - 31/12 X X = 1 X = > x = 2

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