Find the slope of the curve at the given point. 2y+7x=5y+4x at (1,1) The slope of the curve 2y+7x=5y + 4x at (1,1) is . (Type a simplified fraction.) Find the tangent line and the normal line to the curve at the given point. xy2=81, (1,-9) The tangent line to the curve x2y2=81 at (1,-9) is y = 9x-18. The normal line to the curve x2 y2 =81 at (1, -9) is y = 1 (x-80)