Find the standard form of the equation of the parabola using the information given. Focus: (2, 0); Directrix: y = -6 O (y + 3)2 = 12(x - 2) O (x+ 3)2 = 12(y - 2) (x - 2)2 = 12(y + 3) (y - 2)2 = 12(x + 3) eviousGraph the ellipse and locate the foci. = 1 16 +Graph the polar equation. 3 Identify the directrix and vertex. r = 3+3 sine directrix: 1 unit(s) aboveD Question 5 5 pts Identify the conic section that the polar equation represents. Describe the location of a directrix from the focus located at the pole. 5 r= 12+4 cose ellipse; The directrix is = unit(s) to the right of the pole at x - - ellipse; The directrix is = unit(s) below the pole at y = - - ellipse; The directrix is - unit(s) above the pole at y = - ellipse; The directrix is - unit(s) to the left of the pole at x - - 7 inucD Question 6 Find a set of parametric equations for the rectangular equation. y = x4+3 O x = 12; y=+2+3 O x = t; y=+2+ 3 O x = t; y=14 + 3 O x = 12; y=+4+3 PreviousD Question 7 Eliminate the parameter. Write the resulting equation in standard form. A hyperbola: X = 1 + 5 sec t, y = 5 + 3 tant O ( x +5)2 _(v + 1)2 - 1 25 9 O (x- 1)2 + (v - 5 - 1 25 9 O (x - 1)2 _ (v - 52 = 1 25 9 O (x - 5)2 . (v -1)2 25 =1Eliminate the parameter. Write the resulting equation in standard form. A hyperbola: x = 1 + 5 sec t, y = 5 + 3 tant O (x + 5)2 _ (y + 1)2 - 1 25 9 O (x- 1)2 , ( y - 5)2 = 1 25 9 (x - 1)2 (v-5)2 25 - 1 9 x - 52 ( - 12 25