Find the time, in hours, required for the evaporation of $10$ grams of $15$ grams of spherical naphthalene particles suspended in a large air at rest under $45\backslash$deg C and $1\mathrm{.}01325$ bar pressure. Under the given conditions, the diffusion coefficient of naphthalene is $6\mathrm{.}92\backslash$times $10-6$m$2$s$-1,$ its density is $1140$ kg m$-3,$ the sublimation pressure at $45\backslash$deg C is $0\mathrm{.}8654$ mmHg and the molar weight of naphthalene is $128$ kg kmol$-1.(1$ atm $=1\mathrm{.}01325$ bar$)$