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Find y in terms of x. dy = x2 (1-x3) 's, curve passes through (1,8) The solution is y =] ind y in terms ofx
Find y in terms of x. dy = x2 (1-x3) 's, curve passes through (1,8) The solution is y =]
ind y in terms ofx dy x2(1 _ 13) 3 , curve passes through (1 ,8) dx The solution is y
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