Finding the inverse of a 2/2 Ata al A'=_1/ab-bc La 1- a and d swap positions 2- band c switch their sign 3- The result divide by the determinant of the original matrix. To see why: A* A'= 1/ad-bs[.. be[ lla ] Ladce [ad, bc ad - bc -ac + ac bd ad - bc) 1/ad-bc * ad-bad 1 0 0 1 That explains the inverse process. Finding the inverse of a 2/2 Ata al A'=_1/ab-bc La 1- a and d swap positions 2- band c switch their sign 3- The result divide by the determinant of the original matrix. To see why: A* A'= 1/ad-bs[.. be[ lla ] Ladce [ad, bc ad - bc -ac + ac bd ad - bc) 1/ad-bc * ad-bad 1 0 0 1 That explains the inverse process