Question
First, vitamin C (C 6 H 8 O 6 ) reacts with molecular iodine (I 2 , dark brown color) to produce the iodide ion
First, vitamin C (C6H8O6) reacts with molecular iodine (I2, dark brown color) to produce the iodide ion (I−, colorless):
C6H8O6 (aq) + I2 (aq) → 2 H+ (aq) + 2 I− (aq) + C6H6O6 (aq) (Reaction 1)
When hydrogen peroxide is added, the iodide ion is oxidized back to molecular iodine:
2 I− (aq) + 2 H+ (aq) + H2O2 (aq) → I2 (aq) + 2 H2O (l) (Reaction 2)
Use the dilution equation (M1V1 = M2V2) to calculate the concentrations of each reagent in the reaction mixture immediately after the solutions in Beaker 1 and Beaker 2 are mixed (the total volume is 30 mL for all experiments). These are the “initial concentrations” for the reaction, [C6H8O6]0 , [I−]0 , and [H2O2]0 .
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Chemistry The Central Science
Authors: Theodore Brown, Eugene LeMay, Bruce Bursten, Catherine Murphy, Patrick Woodward
12th edition
321696727, 978-0132175081, 978-0321696724
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