For 27 I only need B and the answer was wrong 0.966

27. A political pollster is conducting an analysis of sample results in order to make predictions on election night. Assuming a two-candidate election, if a specific candidate receives at least 53% of the vote in the sample, that candidate will be forecast as the winner of the election. You select a random sample of 100 voters. Complete parts (a) through (c) below.

a.	What is the probability that a candidate will be forecast as the winner when the population percentage of her vote is 50.1%?

The probability is 0.2810 that a candidate will be forecast as the winner when the population percentage of her vote is 50.1%.

(Round to four decimal places as needed.)

b.	What is the probability that a candidate will be forecast as the winner when the population percentage of her vote is 60%?

The probability is enter your response here that a candidate will be forecast as the winner when the population percentage of her vote is 60%.

(Round to four decimal places as needed.)

for 28 I only need part e. and it is not 0.4207.

28) A random sample of n=81 observations is drawn from a population with a mean equal to 20 and a standard deviation equal to 9.

a. Give the mean and standard deviation of the (repeated) sampling distribution x.

x=2020

x=11

(Type integers or decimals.)

b. Describe the shape of the sampling distribution of x.

Does this answer depend on the sample size? Choose the correct answer below.

A. The shape is that of a normal distribution and does not depend on the sample size.

B. The shape is that of a uniform distribution and does not depend on the sample size.

C.The shape is that of a normal distribution and depends on the sample size.

Your answer is correct.

D. The shape is that of a uniform distribution and depends on the sample size.

c. Calculate the standard normal z-score corresponding to a value of x=19.6.

z=negative 0.4

(Type an integer or a decimal.)

d. Calculate the standard normal z-score corresponding to a value of

x=21.5

z=1.5

(Type an integer or a decimal.)

e. Find Px<19.6.

Px<19.6=enter your response here

(Round to four decimal places as needed.)

13) If, in a one-tail hypothesis test, the p-value=0.4127, what is the statistical decision if the null hypothesis is tested at the 0.08 level of significance?

What is the statistical decision?

A. Since the p-value is greaterthanorequalto =0.08, reject H0.

B. Since the p-value is lessthan =0.08, reject H0.

C. Since the p-value is lessthan =0.08, donotreject H0.

D. Since the p-value is greaterthanorequalto =0.08, donotreject h0.

14) Assume a significance level of =0.01 and use the given information to complete parts (a) and (b) below.

Original claim: The mean pulse rate (in beats per minute) of a certain group of adult males is 72 bpm. The hypothesis test results in a P-value of 0.0684.

a. State a conclusion about the null hypothesis. (Reject H0 or fail to reject H0.)

Choose the correct answer below.

A. Reject H0 because the P-value is greaterthan .

B. Failtoreject H0 because the P-value is greaterthan .

C. Reject H0 because the P-value is lessthanorequalto .

D. Failtoreject H0 because the P-value is lessthanorequalto .

17) If a hypothesis test were conducted using =0.05, for which of the following p-values would the null hypothesis be rejected?

a.

0.011

b.

0.06

a. What is the conclusion for a p-value of 0.011?

A. Reject the null hypothesis since the p-value is notless than the value of .

B. Donotreject the null hypothesis since the p-value is notless than the value of .

C. Donotreject the null hypothesis since the p-value is less than the value of .

D. Reject the null hypothesis since the p-value is less than the value of .

b. What is the conclusion for a p-value of 0.06?

A. Reject the null hypothesis since the p-value is less than the value of .

B.Donotreject the null hypothesis since the p-value is notless than the value of .

C. Donotreject the null hypothesis since the p-value is less than the value of.

D. Reject the null hypothesis since the p-value is notless than the value of .

18) If you use a 0.05 level of significance in a two-tail hypothesis test, what is your decision rule for rejecting

H0: =16.9 if you use the Z test?

Which of the following decision rules is correct?

A. Reject H0 if 1.96

B. Reject H0 if ZSTAT<1.645 or ZSTAT>1.645.

C. Reject H0 if ZSTAT<1.96 or ZSTAT>1.96.

D. Reject H0 if 1.645

26) The director of a state agency believes that the average starting salary for clerical employees in the state is less than $27,000 per year. To test her hypothesis, she has collected a simple random sample of 100

starting clerical salaries from across the state and found that the sample mean is $26,800.

a.	State the appropriate null and alternative hypotheses.
b.	Assuming the population standard deviation is known to be $3,500 and the significance level for the test is to be 0.005, what is the critical value (stated in dollars)?
c.	Referring to your answer in part b, what conclusion should be reached with respect to the null hypothesis?
d.	Referring to your answer in part c, which of the two statistical errors might have been made in this case? Explain.

a. State the appropriate null and alternative hypotheses. Choose the correct answer below.

A. H0: =27,000

HA: 27,000

B. H0: =26,800

HA: 26,800

C. H0: 26,800

HA: >26,800

D. H0: 27,000

HA: >27,000

E. H0: 26,800

HA: <26,800

F. H0: 27,000

HA: <27,000

b. What conclusion should be reached based on your answer to part b?

a) Donotreject the null hypothesis.

b) Reject the null hypothesis.

c. Which of the two statistical errors might have been made in this case? Explain.

A. A Type II error might have been made because the null hypothesis was rejected.

B. A Type I error might have been made because the null hypothesis was notrejected.

C. A Type I error might have been made because the null hypothesis was rejected.

D. A Type II error might have been made because the null hypothesis was notrejected.

27)The final scores of games of a certain sport were compared against the final point spreads established by odds makers. The difference between the game outcome and point spread (called a point-spread error) was calculated for 225 games. The mean error is x=0.9. The population standard deviation of the point-spread error = 11.1. Use this information to test the hypothesis that the true mean point-spread error for all games differs from 0. Conduct the test at =0.01 and interpret the result.

Determine the null and alternative hypotheses. Choose the correct answer below.

A. H0:0 0

Ha: 0<0

B. H0:0=0

Ha: 00

C. H0: 0 0

Ha: 0>0

D. H0: 00

Ha: 0=0

The test statistic Z= enter your response here

(Round to two decimal places as needed.)

The p-value= enter your response here

(Round to three decimal places as needed.)

What is the appropriate conclusion at =0.01?

A. Donotreject H0. There is insufficient evidence to conclude that the true mean point-spread error for all games differs from 0.

B. Donotreject H0. There is sufficient evidence to conclude that the sample mean point-spread error for all games differs from 0.

C. Reject H0. There is insufficient evidence to conclude that the sample mean point-spread error for all games differs from 0.

D. Reject H0. There is sufficient evidence to conclude that the true mean point-spread error for all games differs from 0.

29) A manufacturer produces plastic golf tees. The injector molder produces golf tees that are designed to have an average height of 63 mm. To determine if this specification is met, random samples are taken from the production floor. One sample is contained in the table below.

a.	Determine if the process is not producing the tees to specification. Use a significance level of 0.10.
b.	If the hypothesis test determines the specification is not being met, the production process will be shut down while causes and remedies are determined. At times this occurs even though the process is functioning to specification. What type of statistical error would this be?

a. State the appropriate null and alternative hypotheses. Choose the correct answer below.

A. H0: 63

HA: =63

B. H0: 63

HA: <63

C. H0: 63

HA: >63

D. H0: <63

HA: 63

E. H0: =63

HA: 63

F. H0: >63

HA: 63

Determine the critical value(s) for =0.10.

t Subscript alphat , plus or minus t Subscript alpha divided by 2t/2 /, negative t Subscript alphat

=enter your response here

(Use a comma to separate answers as needed. Round to four decimal places as needed.)

Calculate the test statistic.

t=enter your response here

(Round to four decimal places as needed.)

State the conclusion. Choose the correct answer below.

A. Reject the null hypothesis. There is sufficient evidence that the golf tees do not have an average height of

63 mm.

B. Reject the null hypothesis. There isnot sufficient evidence that the golf tees do not have an average height of 63 mm.

C. Donotreject the null hypothesis. There is sufficient evidence that the golf tees do not have an average height of 63 mm.

D. Donotreject the null hypothesis. There isnot sufficient evidence that the golf tees do not have an average height of 63 mm.

b. If the hypothesis test determines the specification is not being met, the production process will be shut down. If this occurs even though the process is functioning to specification, what type of statistical error would this be?

a) Type I error

b) Type II error

29) Researchers determined that 60 tissues is the mean number of tissues used during a cold. Suppose a random sample of 100 tissue users yielded the following data on the number of tissues used during a cold: X=52, S=22.

Using the sample information provided, calculate the value of the test statistic.

A. t=5260/ 22/ 100

B. t=5260/22/10

C. t=5260/22

D. t= 52-60/22/100^2

30) Researchers determined that 60 tissues is the mean number of tissues used during a cold. Suppose a random sample of 100 tissue users yielded the following data on the number of tissues used during a cold: X=52, S=22. Suppose the alternative you wanted to test was H1: <60.

State the correct rejection region for =0.05.

A. Reject H0 if t>1.6604.

B. Reject H0 if t<1.6604.

C. Reject H0 if t>1.9842 or Z<1.9842.

D. Reject H0 if t<1.9842.

31) You are the manager of a restaurant for a fast-food franchise. Last month, the mean waiting time at the drive-through window for branches in your geographical region, as measured from the time a customer places an order until the time the customer receives the order, was 3.7 minutes. You select a random sample of

81 orders. The sample mean waiting time is 3.95 minutes, with a sample standard deviation of 0.9 minute. Complete parts (a) and (b) below.

a. At the 0.10 level of significance, is there evidence that the mean waiting time is different from

3.7 minutes? Choose the correct null and alternative hypotheses to decide this:

A. H0: 3.95H1:=3.95

B. H0: 3.7 H1:< 3.7

C. H0: =3.7H1:3.7

D. H0: X =3.7H1: X 3.7

Determine the test statistic.

The test statistic is enter your response here.

(Round to two decimal places as needed.)

Find the p-value.

p-value = enter your response here

(Round to three decimal places as needed.)

State the conclusion.

(Reject / Do not reject )H0.

There is ( sufficient / insufficient) evidence to conclude that the population mean waiting time is different from 3.7 minutes.

b. Because the sample size is 81, do you need to be concerned about the shape of the population distribution when conducting the t test in (a)?

Explain. Choose the correct answer below.

A. Yes, because n is equal to 81, the sampling distribution of the t test cannot be determined. In general, the t test requires a larger sample size.

B. Yes, because n is equal to 81, the sampling distribution of the t test cannot be determined. In general, the t test is only appropriate for a normally distributed sample.

C. No, because n is equal to 81, the sampling distribution of the t test is approximately normal. In general, the t test is appropriate for this sample size unless the population is skewed.

D. No, because n is equal to 81, the sampling distribution of the t test is approximately normal. In general, the t test is appropriate for a large sample size.

32) A report states that the cost of repairing a hybrid vehicle is falling even while typical repairs on conventional vehicles are getting more expensive. The most common hybrid repair, replacing the hybrid inverter assembly, had a mean repair cost of $3,927 in 2012. Industry experts suspect that the cost will continue to decrease given the increase in the number of technicians who have gained expertise on fixing gas-electric engines in recent months. Suppose a sample of 100 hybrid inverter assembly repairs completed in the last month was selected. The sample mean repair cost was $3,840 with the sample standard deviation of $300.

Complete parts (a) and (b) below.

a. Is there evidence that the population mean cost is less than $3,927? (Use a 0.05 level of significance.)

State the null and alternative hypotheses.

H0: greater than> greater than or equals equals= less than< not equals less than or equals $enter your response here.

H1: not equals equals= less than or equals greater than or equals greater than> less than< $enter your response here. (Type integers or decimals.)

Find the test statistic for this hypothesis test.

test statistic = enter your response here

(Round to two decimal places as needed.)

The critical value(s) for the test statistic is(are) enter your response here.

(Round to two decimal places as needed. Use a comma to separate answers as needed.)

Is there sufficient evidence to reject the null hypothesis using =0.05?

A. Reject the null hypothesis. There is sufficient evidence at the 0.05 level of significance that the population mean cost is greater than $3,927.

B. Reject the null hypothesis. There is sufficient evidence at the 0.05 level of significance that the population mean cost is less than $3,927.

C. Donotreject the null hypothesis. There is insufficient evidence at the 0.05 level of significance that the population mean cost is less than $3,927.

D. Donotreject the null hypothesis. There is insufficient evidence at the 0.05 level of significance that the population mean cost is greater than $3,927.

b. Determine the p-value and interpret its meaning.

The p-value is enter your response here.

(Round to three decimal places as needed.)

What does this p-value mean given the results of part (a)?

A. The p-value is the probability that the actual mean cost is $3,840 or less.

B. The p-value is the probability that the actual mean cost is $3,927 or less given the sample mean cost is $3,840.

C. The p-value is the probability that the actual mean cost is more than $3,840.

D. The p-value is the probability of getting a sample mean cost of $3,840 or less if the actual mean cost is $3,927.

33) A hospital was concerned about reducing its wait time. A targeted wait time goal of 25 minutes was set. After implementing an improvement framework and process, a sample of 363 patients showed the mean wait time was 23.18 minutes, with a standard deviation of 16.02 minutes. Complete parts (a) and (b) below.

a. If you test the null hypothesis at the 0.05 level of significance, is there evidence that the population mean wait time is less than 25 minutes?

State the null and alternative hypotheses.

A. H0: >25.

H1: <25

B. H0: 25

H1: 25

C. H0: <25

H1: 25

D. H0: 25

H1: 25

E. H0: 25

H1: <25

F. H0: <25

H1: >25

Find the test statistic for this hypothesis test.

test statistic = enter your response here

(Type an integer or a decimal. Round to two decimal places as needed.)

Find the p-value.

The p-value is enter your response here.

(Type an integer or a decimal. Round to three decimal places as needed.)

Is there sufficient evidence to reject the null hypothesis? (Use a 0.05 level of significance.)

A. Reject the null hypothesis. There is sufficient evidence at the 0.05 level of significance that the population mean wait time is greater than 25 minutes.

B. Donotreject the null hypothesis. There is insufficient evidence at the 0.05 level of significance that the population mean wait time is greater than 25 minutes.

C. Reject the null hypothesis. There is sufficient evidence at the 0.05 level of significance that the population mean wait time is less than 25 minutes.

D. Donotreject the null hypothesis. There is insufficient evidence at the 0.05 level of significance that the population mean wait time is less than 25 minutes.

b. Interpret the meaning of the p-value in this problem.

Choose the correct answer below.

A. The p-value is the probability that the actual mean wait time is 23.18 minutes or less.

B. The p-value is the probability that the actual mean wait time is more than 23.18 minutes.

C. The p-value is the probability of getting a sample mean wait time of 23.18 minutes or less if the actual mean wait time is 25 minutes.

D. The p-value is the probability that the actual mean wait time is 25 minutes given the sample mean wait time is 23.18 minutes.

35) The marketing manager for an automobile manufacturer is interested in determining the proportion of new compact-car owners who would have purchased a GPS navigation system if it had been available for an additional cost of $300. The manager believes from previous information that the proportion is 0.30. Suppose that a survey of 200 new compact-car owners is selected and 79 indicate that they would have purchased the GPS navigation system. If you were to conduct a test to determine whether there is evidence that the proportion is different from 0.30, which test would you use?

A. t test of a population proportion

B. Z test of a population proportion

C. t test of population mean

D. Z test of a population mean

43) A survey claims that 9 out of 10 doctors recommend aspirin for their patients with headaches. To test this claim against the alternative that the actual proportion of doctors who recommend aspirin is less than 0.90, a random sample of 100 doctors results in 83 who indicate that they recommend aspirin. What is the value of the test statistic in this problem, rounded to two decimal places?

A. 2.33

B. 0.07

C.1.86

D. 4.12