For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature: P o T (T in kelvins) and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to: 0. 0029 Amax T (2max in meters, T in kelvins) Assume an object is emitting blackbody radiation. If the Kelvin temperature of an object is doubled, the amount of radiant energy emitted each second is the original amount. O 1/16th O half O the same as O 2 times O 16 times