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For a continuous function f, let Ave(x) be the function defined for x>0 Ave(x) = 1/x integral from 0 to x f(t)dt Find Ave(x) where

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For a continuous function f, let Ave(x) be the function defined for x>0 Ave(x) = 1/x integral from 0 to x f(t)dt Find Ave(x) where f(x) = x2 Using the product rule, show that for any continuous function f defined on [0,infinity), Ave(x) + Ave'(x) = f(x) for al x>0

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