For a data set obtained from a sample of size n = 144 with; = 47.75, it is known that a= 5.4. la) What is the point estimate of p? u = l lb) Find 2 score corresponding to a 95% condence level, 20/2. Recall that (1 a)100% = 95%. Round the answer to two decimal places. (c) Construct a 95% condence interval for p. Round the answers to four decimal places. ld) What is the margin of error in part (c)? Round the answer to four decimal places. E=n Chapter 08, Section 8.2, Intelligent Tutoring Problem 017 Your answer is incorrect. Determine the sample size for the estimate of u if the margin of error E = 0.04, o = 0.80, and the confidence level is 99%. Round the answer up to the next whole number. n = i e Textbook and Media Save for Later Last saved 25 seconds ago. Attempts: 2 of 5 used Submit Answer Saved work will be auto-submitted on the due date. Auto- submission can take up to 10 minutes.It is said that happy and healthy workers are efficient and productive. A company that manufactures exercising machines wanted to know the percentage of large companies that provide on-site health club facilities. A sample of 240 such companies showed that 96 of them provide such facilities on site. Construct a 99% confidence interval for the percentage of all such companies that provide such facilities on site. What is the margin of error for this estimate? Round your answers to one decimal place. Confidence interval: i % to i ! % Margin of error: 8 %Consider Ho: H = 28 versus H1: M # 28. A random sample of 25 observations taken from this population produced a sample mean of 24.71. The population is normally distributed with o = 7. Note: Use Table IV in Appendix C to compute the probabilities. (a) Calculate the p-value. Round the answer to four decimal places. p-value = HI (b) Would you reject the null hypothesis if the test were made at the significance level of 0.05? Do not reject v the null hypothesis. (c) Would you reject the null hypothesis if the test were made at the significance level of 0.01? Reject the null hypothesis.Lazurus Steel Corporation produces iron rods that are supposed to be 36 inches long. The machine that makes these rods does not produce each rod exactly 36 inches long. The lengths of the rods are normally distributed and vary slightly. It is known that when the machine is working properly, the mean length of the rods is 36 inches. The standard deviation of the lengths of all rods produced on this machine is always equal to 0.035 inch. The quality control department at the company takes a sample of 20 such rods every week, calculates the mean length of these rods, and tests the null hypothesis, [1 = 36 inches, against the alternative hypothesis, H 75 36 inches. If the null hypothesis is rejected, the machine is stopped and adjusted. A recent sample of 20 rods produced a mean length of 36.015 inches. Calculate the p-value for this test of hypothesis. Based on this p-value, will the quality control inspector decide to stop the machine and adjust it if he chooses the maximum probability of a Type I error to be 0.01? Use the normal distribution table. Round your answer to four decimal places. Wu II In a hypothesis test with hypotheses Ho : p 0.58, a random sample of size 1102 produced a sample proportion of 0.6010. The test is to be made at the 2.5% significance level. What is the critical value of z? O 1.96 O 2.58 O 2.33 O 1.65 What is the value of the test statistic, z, rounded to three decimal places? What is the p-value for this hypothesis test, rounded to four decimal places? Should you reject or fail to reject the null hypothesis in this test? Fail to reject. vIn a hypothesis test with hypotheses Ho : p 2 0.31 and H1 : p