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For a unit cube containing a dispersion of 2nd phase particles with radius r the number of particles Nv=4/3r3f. The average distanced between particles is
For a unit cube containing a dispersion of 2nd phase particles with radius r the number of particles Nv=4/3r3f. The average distanced between particles is given by the equation =(Nv)3112r (a) Show that =2r[(1.91f1)1/31] (b) For f=0.001,0.01,0.1 and r=106,105,104 and 103cm, calculate . (c) Plot f versus
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