for agiven l=1000 bits tAB= 5 ms (propagation time A to B),RAB= 1.5Mbps data rate Ato B), workout the w for sliding window as near to 100% efficency as possible) 2 for a given l= 1000 bits , tAB = 5ms RAB= 1.5Mbps W=5, calculate the efficency between A nad B( to one dicimal place) 3,for a given l=1000, bits tAB= 5ms RAB= 1.5 Mbps window size= 4 for Ato B and given tBC=1.0msec(propogation time between Band C), calculate the data rate between Band Cin bps for stop and wait so that B can balance with arrivals from A and send them out before there is an over-run ( buffering overwrite) roundup the nearest integer.