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For f(x) = 3 + sin(x) - x 2 : a) show that there is a root in the interval [1,2]. b) With x 1
For f(x) = 3 + sin(x) - x2:
a) show that there is a root in the interval [1,2].
b) With x1 =1, use Newton's method to estimate the value of the root. Round each intermediate xn and the value of the root to six decimal places.
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