Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

For my program below that is in C++ I have the different parts below that I have to make sure my code has completed or

For my program below that is in C++ I have the different parts below that I have to make sure my code has completed or needs to include. Also I need to implement in my code that has the capability of measuring the actual sorting time (https://stackoverflow.com/questions/5248915/execution-time-of-c-program) heres a reference link I was given. I also attached a screenshot of the input files that I am suppose to measure the running time but im just only including for you to see what I am suppose to measure.image text in transcribed

a) my program is well commented

b) The program reads input from a data file specified by user and write the sorted output into another file;

c) Design your program in the way that it can accept users options such as:

*. Which sort algorithm to use;

*. Which sort order to use, that is, non-decreasing order or non-increasing order?

*. Whether should the output remove duplications?

d) Also I need to implement in my code that has the capability of measuring the actual sorting time (https://stackoverflow.com/questions/5248915/execution-time-of-c-program) heres a reference link I was given.

#include

#include

#include

#include

#include

using namespace std;

void insertionsort(int array[],int n){

int i, key, j;

for (i= 1; i

key= array[i];

j=i-1;

while (j >= 0 && array[j]>key){

array[j+1] = array[j];

j = j-1;

}

array[j+1] = key;

}

ofstream out("inputFile.txt");

for(i=0;i

out

cout

out.close();

}

void merge(int arr[], int l, int m, int r){

int i, j, k;

int n1 = m - l + 1;

int n2 = r - m;

int L[n1], R[n2];

for (i = 0; i

L[i] = arr[l + i];

}

for (j = 0; j

R[j] = arr[m + 1+ j];

i = 0;

j = 0;

k = l;

}

while (i

if (L[i]

arr[k] = L[i];

i++;

}

else{

arr[k] = R[j];

j++;

}

k++;

}

while (i

arr[k] = L[i];

i++;

k++;

}

while (j

arr[k] = R[j];

j++;

k++;

}

}

void mergeSort(int arr[], int l, int r){

if (l

int m = l+(r-l)/2;

mergeSort(arr, l, m);

mergeSort(arr, m+1, r);

merge(arr, l, m, r);

}

}

void swap(int *a, int *b){

int x = *a;

*a = *b;

*b = x;

}

int partition (int arr[], int low, int high){

int pivot = arr[high];

int i = (low - 1);

for (int j = low; j

if (arr[j]

i++;

swap(&arr[i], &arr[j]);

}

}

swap(&arr[i + 1], &arr[high]);

return (i + 1);

}

void quickSort(int arr[], int low, int high){

if (low

int z = partition(arr, low, high);

quickSort(arr, low, z - 1);

quickSort(arr, z + 1, high);

}

}

int removeDuplicates(int array[], int n){

if (n==0 || n==1)

return n;

int j = 0;

for (int i=0; i

if (array[i] != array[i+1])

array[j++] = array[i];

array[j++] = array[n-1];

return j;

}

//Sorting the array

void countingSort(int *input, size_t num_elements) {

size_t max = *std::max_element(input, input+num_elements);

std::vector counts(max+1);

for (int i=0; i

++counts[input[i]];

int temp = input[0];

input[0] = input[num_elements-1];

int ntemp = input[num_elements-2];

input[num_elements-2] = temp;

input[num_elements-1] = ntemp;

}

int main(int argc,char *argv[]){

int array[],i=0,j,count=0,k;

ifstream input;

input.open(argv[1]);

if(input.fail()) {

cout

}

else{

while(input.eof()==0){

input>>array[i];

i=i+1;

count=count+1;

}

string s;

cout

cin >> s;

if(s==std::string("insert")){

insertionsort(array,count);

ofstream out("inputFile.txt");

for(i=0;i

out

}

cout

out.close();

}

else if(s==std::string("quick")){

quickSort(array,0,count-1);

ofstream out("inputFile.txt");

for(i=0;i

out

}

cout

out.close();

}

else if(s==std::string("merge")){

mergeSort(array,0,count);

ofstream out("inputFile.txt");

for(i=0;i

out

cout

out.close();

}

else if(s==std::string("count")){

countingSort(array, count);

ofstream out("inputFile.txt");

for(i=0;i

out

cout

}

cout

out.close();

}

else{

cout

}

file10 txt (file10.txt), file 100 txt (file100.txt), file 1000 txt (file1000.txt), file 10000 txt (file10000.txt), file100000 txt (file100000.txt), f file1000000.bxt (ile 1000000.txt) file10 txt (file10.txt), file 100 txt (file100.txt), file 1000 txt (file1000.txt), file 10000 txt (file10000.txt), file100000 txt (file100000.txt), f file1000000.bxt (ile 1000000.txt)

<>

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image_2

Step: 3

blur-text-image_3

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Modern Database Management

Authors: Jeff Hoffer, Ramesh Venkataraman, Heikki Topi

13th Edition Global Edition

1292263350, 978-1292263359

More Books

Students also viewed these Databases questions

Question

> describe selected cases involving disability discrimination

Answered: 1 week ago