For n bits input, the number of bits in the output of mealy machine is always equal to

$\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ and the number of bits in Moore machine is always equal to

$\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_.$ Thus, the number of output bits in case of Moore machine is

always $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ less than number of output bits in mealy machine.