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For the circuit shown below, F = 1 if i . e . ( : A 1 A 0 = 1 0 2 } and

For the circuit shown below, F=1 if i.e.(:A1A0=102} and B>5i0. What is the simplest
Boolean expression of F(A1,A0,B2,B1,B0)?
\table[[A)F=A1bar(A0)+B2bar(B1)B0,B)F=(A1,A0)(B2+bar(B1)+B0),C)F=A1bar(A0)B2bar(B1)B0
, Answer all questions please.
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