For the decomposition of

(CH_(3))_(2)O

(species

{

(

:A)

} at

777K

, the time required for

[A]_(0)

to fall to

0.69[A]_(0)

as a function of

[A]_(0)

is:\ \\\\table[[

10^(3)([A]_(0))/(mo(l)/(d)m^(3))

,8.13,6.44,3.10,1.88],[

(t_(0.69))/(s)

,590,665,900,1140]]\ (a) Find the order of the reaction.\ (b) Find

k_(A)

in

d(A)/(d)t=-k_(A)[A]^(n)

.

For the decomposition of (CH3)2O (species A) at 777K, the time required for [A]0 to fall to 0.69[A]0 as a function of [A]0 is: (a) Find the order of the reaction. (b) Find kA in d[A]/dt=kA[A]n