For the following NMOS and NPN BJT Circuit, calculate using hand calculations:

• DC Q Points for M3 and M4
• Small signal AC analysis for both common mode and differential model on differential pairs
• Common Mode Rejection Ratio

Please make sure to explain the derivations for small signal AC analysis

For the following NMOS and NPN BJT Circuit, calculate using hand calculations: DC Q Points for M3 and M4 > Small signal AC analysis for both common mode and differential model on differential pairs Common Mode Rejection Ratio V2 > v3 7-12 RD3 5k R10 4.66k Vdiff M3 Q3 NPN TTT 04 NPN C3 C4 Vo1 HI BS170 M4 BS170 R17 Vo2 1 R8 1P R9 500 500 11 Vmirr2 V. .MODEL BS170 VDMOS VTO=2.38 RG=270 RS=1.572 RD=1.436 RB=.768 KP=.05 Cgdmax=20p Cgdmin=3p CGS=28p Cjo=35p Rds=1.2E8 IS=5p Bv=60 lbv=10u Tt=161.6n For the following NMOS and NPN BJT Circuit, calculate using hand calculations: DC Q Points for M3 and M4 > Small signal AC analysis for both common mode and differential model on differential pairs Common Mode Rejection Ratio V2 > v3 7-12 RD3 5k R10 4.66k Vdiff M3 Q3 NPN TTT 04 NPN C3 C4 Vo1 HI BS170 M4 BS170 R17 Vo2 1 R8 1P R9 500 500 11 Vmirr2 V. .MODEL BS170 VDMOS VTO=2.38 RG=270 RS=1.572 RD=1.436 RB=.768 KP=.05 Cgdmax=20p Cgdmin=3p CGS=28p Cjo=35p Rds=1.2E8 IS=5p Bv=60 lbv=10u Tt=161.6n