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For the following reaction, 1/4 P4(s) + 3/2 H2(g) PH3(g), the corresponding standard Gibbs energy of reaction, rG is +13.4 kJ/mol at 298K. At non-equilibrium

For the following reaction, 1/4 P4(s) + 3/2 H2(g) PH3(g), the corresponding standard Gibbs energy of reaction, rG is +13.4 kJ/mol at 298K. At non-equilibrium condition, determine the reaction Gibbs energy, rG, when the partial pressure of H2 and PH3 (both treated as ideal gases) are 1 bar and 0.6 bar, respectively? What is the spontaneous direction of the reaction in this case?

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