For the following reaction, $66\mathrm{.}8$ grams of barium chloride are allowed to react with $52\mathrm{.}5$ grams of potassium sulfate.

barium chloride $(aq)+$ potassium sulfate $(aq)$ barium sulfate $(s)+$ potassium chloride $(aq)$

What is the maximum amount of barium sulfate that can be formed?

Mass $=$

What is the FORMULA for the limiting reactant?

What amount of the excess reactant remains after the reaction is complete?

Mass $=$