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For the reaction: EO+WAEG The rate law is: r= (0.1113 Peo Pw)/(1+0.475Peo+0.322Pw+0.414PEG 12 Neglecting pressure drop, calculate the catalyst weight necessary to achieve 80% conversion

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For the reaction: EO+WAEG The rate law is: r= (0.1113 Peo Pw)/(1+0.475Peo+0.322Pw+0.414PEG 12 Neglecting pressure drop, calculate the catalyst weight necessary to achieve 80% conversion in a fluidised CSTR, given a stoichiometric molar feed of the reactants for a total rate of 700 mol/h, and the reactor is operated at 3 atm and 200C. Please note the units are set to work out as g of catalyst, but please submit the answer as kg of catalyst, with two decimal places. Relevant Equations: For a CSTR: W = (FAX)/ra E = YA08 = (NTF-Nto)/NTO P = Paol(O; + v;X)/(1+ X)] where v; is the stochiometric coefficient (b/a, c/a, d/a, etc) which is positive for products and negative for reactants a "stoichiometric feed" means that the feed ratio follow the stoichiometry of the reaction, so in this case, it is 1 to 1

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