Question
For the reaction of A to form B over a solid catalyst, the reaction rate has the form: r=kK A P A /[1+K A P
For the reaction of A to form B over a solid catalyst, the reaction rate has the form: r=kKAPA/[1+KAPA+KBPB]2. However, there is a large excess of inert in the reactant stream that is known to readily adsorb on the catalyst surface. How will this affect the reaction order with respect to A?
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Sustainable Engineering Principles And Practice
Authors: Bhavik R. Bakshi
1st Edition
1108420451, 9781108420457
