For the second part of the question, it says to think of the smallest cube that contains all of h=0(which defines the shell)

W ,9, 2) = 520 ((1-2 - - * - -) + 2+2 +me+z") (1) can be used to generate a three-dimensional shell (i.e., a level surface) by setting h(x, y, z) = 0. In MATLAB, plot the shell (hint: this is an 'implicit'expression) and use the plot to determine an appropriately sized cube (centered on the origin) that entirely contains the shell. Use the plot option 'daspect([1 1 1])'. Take the total cube edge length to be equal to the smallest integer value that contains the shell. What is the length? W ,9, 2) = 520 ((1-2 - - * - -) + 2+2 +me+z") (1) can be used to generate a three-dimensional shell (i.e., a level surface) by setting h(x, y, z) = 0. In MATLAB, plot the shell (hint: this is an 'implicit'expression) and use the plot to determine an appropriately sized cube (centered on the origin) that entirely contains the shell. Use the plot option 'daspect([1 1 1])'. Take the total cube edge length to be equal to the smallest integer value that contains the shell. What is the length