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For this question you must write a java class called Rectangle and a client class called RectangleClient. The partial Rectangle class is given below. (For

For this question you must write a java class called Rectangle and a client class called RectangleClient. The partial Rectangle class is given below.

(For this assignment, you will have to submit 2 .java files: one for the Rectangle class and the other one for the RectangleClient class and 2 .class files associated with these .java files. So in total you will be submitting 4 files for this problem.)

// A Rectangle stores an (x, y) coordinate of its top/left corner, a width and height. public class Rectangle {

 private int x; private int y; private int width; private int height; 
 // constructs a new Rectangle with the given x,y, width, and height 
 public Rectangle(int x, int y, int w, int h) 
 // returns the fields' values public int getX() public int getY() public int getWidth() 
 public int getHeight() 
 // returns a string such as Coordinate is (5,12) and 

dimension is 4x8 where 4 is width and 8 is height. public String toString()

...

}

  • Write an instance method called area that will be placed inside the Rectangle class. The method returns the area of the rectangle.

  • Write another instance method called changeSize that will be placed inside the Rectangle class. This method changes the height and width of the rectangle. The method accepts newWidth and newHeight as parameters and changes the value of width and height to this new width and height.

  • Write the client class RectangleClient that creates an object of class Rectangle and initializes its x coordinate, y coordinates, width and height to 5, 12, 4, and 8 respectively. Print out the x- coordinate, y-coordinate, width, height (using toString method) and area of this rectangle. Then change the size of this rectangle to width = 3 and height = 10 and then print out the x- coordinate, y-coordinate, width, height area again.

    When you execute the RectangleClient file you result should look like:

    Coordinate is (5,12) and dimension is 4x8 Area is 32 Coordinate is (5,12) and dimension is 3x10 Area after the size is changed is 30

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