Formulate relational algebra queries to find the following information:

$(1)$ Musician$($s$)$ ssn$($s$)$ and names$($s$)$ who play $$Saxophone$.$

$(2)$ Musician$($s$)$ ssn$($s$)$ and names$($s$)$ who share the same address. Assume each musician has only one address.

$(3)$ Album$($s$)$ identifiers and Album$($s$)$ title$($s$)$ produced by the musician$($s$)$ named $$Ben$.$

$(4)$ Musician$($s$)$ ssn$($s$)$ and names$($s$)$ who play all instruments that are played by $$Ben$.$

$(5)$ Titles of albums produced by musicians who play both $$guitar$$ and $$piano$.$

$(6)$ Musicians$$ ssn$($s$)$ and name$($s$)$ performed song with songID $544$ or produced an album that contains that song.

$(7)$ Album$($s$)$ identifiers and Album$($s$)$ title$($s$)$ with the highest speed.

$(8)$ Song ID$($s$)$ and title$($s$)$ that are not performed by any musician.

$(9)$ Song ID$($s$)$ and title$($s$)$ performed by musician$($s$)$ who have produced at least two albums.

$(10)$ Musician$($s$)$ ssn$($s$)$ and name$($s$)$ with annual income more than $$50,000$ and have not produced any album.

Note : Can't join more than two tables at once $,$ you can rename two joined tables and join it with third table

use the schema below for reference

Relation Schemas

Musicians$($ssn: string, name: string, annualIncome: real$)$ Primary Key: ssn

Candidate Key: None

Foreign Key: None

Instruments$($instrID: string, iname: string, musickey: string$)$ Primary Key: instrID

Candidate Key: iname

Foreign Key: None

Plays$($ssn: string, instrID: string$)$ Primary Key: $($ssn$,$ instrID$)$

Candidate Key: None

Foreign Key: ssn$,$ instrID

SongsAppears$($songID: string, authorSSN: string, title: string, albumIdentifier: string$)$

Primary Key: songID

Candidate Key:authorSSN

Foreign Key: albumidentifier

Lives$($ssn: string, aid: string, phone: string$)$ Primary Key: $($ssn$,$ aid$)$

Candidate Key: None

Foreign Key: ssn$,$ aid

Place$($aid: string, address: string, otherInfo: string$)$ Primary Key: aid

Candidate Key: address

Foreign Key:None

Perform$($songID: string, ssn: string$)$ Primary Key: $($songID$,$ ssn$)$

Candidate Key: None

Foreign Key: ssn$,$ songID

AlbumProducer$($albumIdentifier: string, ssn: string, copyrightDate: date, speed: real, title: string$)$

Primary Key: albumIdentifier

Canidate Key: title

Foreign Key: ssn