Answered step by step
Verified Expert Solution
Question
1 Approved Answer
Frequency 6.0 4.5 3.0 1.5 Percent 10 90 99 Residual Plots for Conversion (%) y1 Normal Probability Plot -10 -5 0 Residual Histogram Residual
Frequency 6.0 4.5 3.0 1.5 Percent 10 90 99 Residual Plots for Conversion (%) y1 Normal Probability Plot -10 -5 0 Residual Histogram Residual 10 5 10 50 60 70 Residual 10 Versus Fits Fitted Value Versus Order 80 90 0.0 -5.0 -2.5 0.0 2.5 5.0 7.5 10.0 12.5 2 4 68 10 12 14 16 18 20 Residual Observation Order Frequency Percent 10 Normal Probability Plot Residual Residual Plots for Viscosity (y2) Residual 3.0 1.5 0.0 -1.5 -3.0 0 55 60 Versus Fits Fitted Value Histogram Versus Order 3.0 1.5 0.0 -1.5 65 70 -3.0 -2 -1 0 1 2 3 2 8 10 12 14 16 18 20 Residual Observation Order 1 81 0 -1- Contour Plots of Conversion (%) y1 Time Temperature Catalyst Temperature 97 Hold Values Temperature 0 O O O Time Catalyst 0 0 -1 Catalyst Time 1 0- 73 -1- 81 81 89 81 Contour Plot of Viscosity y2 vs Catalyst, Temperature Catalyst 1.5 59.1 1.0 0.5 0.0 -0.5- 55.7 -1.0 10 -1.5 54.0 65.9 69,3 67,6 64.2 60.8 57,4 -1.5 -1.0 -0.5 0.0 0.5 1.0 1.5 Temperature Optimal Temperat Time High 1.6818 1.6818 Catalyst 1.6818 D: 1.000 Cur [1.0984] [1.6818] Low -1.6818 -1.6818 [0.0552] -1.6818 Composite Desirability D: 1.000 Viscosit Targ: 65.0 y = 65.0 d = 1.0000 Conversi Maximum y = 97.0 d = 1.0000
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started