Fresh n-hexane, C = XCH4.C Beans, A = 100kg XOILA = 0.13 Xsolids A = 0.87 GROUN D MILL (GM) MP Liquid hexane, K = XCH4.K n-hexane, L=300kg XC6H4 K=1.0 Ground Beans, B = 100kg Xoul.B =0.13 Xsolids,B=0.87 EXTRACTOR (EX) CONDEN Extractor Effluent, F = Xoil.F = Xsolids.F = XC6H4 F Hexane vapour,J = Xa Had FILTER (FIL) Liquid Filtrate, H = Xoil.H = XCHH Filter Cake, G = Xoil.G = Xsolids.G=0.75 XCHG = EVAPORA Final Product, I = Xoll =

learner is required to carry out a material balance in the following problem by making necessary assumptions when required. A learner must learn independently to get necessary information on the given process, apply conservation law of mass, and scientific and engineering knowledge to solve the problem. PRODUCTION OF BEAN OIL: Figure 1 shows the production of bean oil process. The process-engineering learner is required to fully label and calculate all the stream masses and compositions unknown. Ensure that all assumption made are clearly supported. In the production of a bean oil in figure 1, beans containing 13.0 wt% oil and 87.0 wt% solids are ground and fed to a stirred tank (the extractor) along with a recycled stream of liquid n-hexane. The feed ratio is 3 kg hexane per kg beans. The ground beans are suspended in the liquid, and essentially all of the oil in the beans is extracted into the hexane. The extractor effluent passes to a filter. The filter cake contains 75.0 wt% bean solids and the balance bean oil and hexane, the latter two in the same ratio in which they emerge from the extractor. The filter cake is discarded and the liquid filtrate is fed to a heated evaporator in which the hexane is vaporized and the oil remains as a liquid. The oil is stored in drums and shipped. The hexane vapour is subsequently cooled and condensed, and the liquid hexane condensate is recycled to the extractor feed