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From previous integration techniques we know that sec t In sec t tan t Use this to evaluate the trig integral from Part 1 and

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From previous integration techniques we know that sec t In sec t tan t Use this to evaluate the trig integral from Part 1 and then substitute back to get the final result in terms of To substitute back in terms of x you would use sec t tan t 2 x 10 10 The final result would then be 3 10 dx 10 2 Vx 10 10 C

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