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function func ( A , x ) : A . sort ( ) result = [ ] Mystery ( A , x , 0 ,

function func(A, x):
A.sort()
result =[]
Mystery(A, x,0,[], result)
return result
function Mystery(A, x, start, p, result):
if x ==0:
result.append(p)
if x <0:
return
for i from start to n-1:
Mystery(A, x - A[i], i +1, p +[A[i], result)
Find an upper bound for its time complexity (T).
Hint: You need to writeT(n,x) as a recurrence relation and solve it by expanding it

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