Gas distributor Q3) A thin film, 1.0 mm thick, coat of fresh paint has just been sprayed over a 1.5m by 1.5msquare steel body part, which Drying chamber approximates a flat surface. The paint contains benzene as the solvent. The paint 60 m3/min air H = 1.0 m surface exerts a partial pressure of 0.137 27C, 1.0 atm (W = 1.5 m) atm at the process temperature of 27C. Sixty cubic meters per minute of air are blown into the rectangular drying chamber Painted as shown above; the chamber measures 1.5 steel plate m in length, 1.0 m in height, and 1.5 m in L = 1.5 m width. The temperature of the air is 27C and the total system pressure is 1.0 atm. Determine the average mass-transfer convective coefficient and the solvent evaporation rate from the surface in g/min, assuming that the concentration of the solvent vapor in the bulk gas is very small. - In question 3, we have benzene (a) - air (b) system. You need to find Dab value at 300K. References (book and internet) has Dab value as 0.0962 cm2/s at 298 K. You can use the temperature correlation that I mentioned for question 1 and find the Dab value at 300K (very minor difference). You also need velocity. Volumetric flowrate of air is given and the duct dimension (cross sectional area) is also given. So Vol.Flow Rate/area = velocity. You can calculate Sc and find Re with these info. With the Re you can determine whether you are in laminar or turbulent region. According to that identify which Sh equation to use. Remember table 2.1, Sh is also equal to k*l/Dab. So find your k value. Finally you need k to solve Na=k*(ca,s-ca,bulk) we can assume ca,bulk~0. What about ca,s? You can calculate that via ideal gas equation as I did last time in class