General Instructions In this assignment, we will be examining 2 One Way ANOVAs and interpreting the results As with previous assignments, the Aspelmeier and Pierce text does a wonderful job of explaining how to actually run the tests in Chapter 8 Follow their instructions for interpreting the SPSS output results I have given you for this assignment ANOVA The researchers want to compare the mean rating of Emotional Support of the groups of where students currently live (1 Dorm, 2 Apartment or House with Peers or Alone, 3 Parents) Also, researchers think that the family composition of the house people grow up in will influence the amount of loyalty females will reported with their closest female friends As we learned from the text and the PPTs, we know these research situations require the use of the ANOVA Here are the researchers' hypotheses The researchers think that students who live at home will report different levels of emotional support from their closest female friends than those students who live either in the dorms or in an apartment or house with peers or alone The researchers also believe that females will report differing levels of loyalty with their closest female friends based on the family composition of the house in which they grew up Use the SPSS data to and make conclusions Part 1The Analyses For this assignment, we will need to run 2 One Way ANOVA Tests one comparing levels of where students currently live and one comparing the family composition of the house in which they grew up Unlike the last assignment, our groups are already formed We also need to run the Tukey multiple comparison procedures Additionally, we need to create a graph for each hypothesis Hypotheses The researchers think that students who live at home will report different levels of emotional support from their closest female friends than those students who live either in the dorms or in an apartment or house with peers or alone The researchers also believe that females will report differing levels of loyalty with their closest female friends based on the family composition of the house in which they grew up Hypothesis One Output Descriptives EmoSupport N Mean Std Deviation Std Error 95 Confidence Interval for Mean Min Max Lower Bound Upper Bound Dorm 34 57 44 7 166 1 229 54 94 59 94 37 64 Apartment or House with Peers or Self 34 56 09 7 012 1 203 53 64 58 53 40 64 Parents 32 55 75 10 479 1 852 51 97 59 53 9 64 Total 100 56 44 8 272 827 54 80 58 08 9 64 Test of Homogeneity of Variances EmoSupport Levene Statistic df1 df2 Sig 191 2 97 827 ANOVA EmoSupport Sum of Squares Df Mean Square F Sig Between Groups 53 522 2 26 761 386 681 Within Groups 6721 118 97 69 290 Total 6774 640 99 Multiple Comparisons EmoSupport Tukey HSD (I) Where do you live (J) Where do you live Mean Difference (I J) Std Error Sig 95 Confidence Interval Lower Bound Upper Bound Dorm Apartment or House with Peers or Self 1 353 2 019 781 3 45 6 16 Parents 1 691 2 050 689 3 19 6 57 Apartment or House with Peers or Self Dorm 1 353 2 019 781 6 16 3 45 Parents 338 2 050 985 4 54 5 22 Parents Dorm 1 691 2 050 689 6 57 3 19 Apartment or House with Peers or Self 338 2 050 985 5 22 4 54 Hypothesis Two Output Descriptives Loyalty N Mean Std Deviation Std Error 95 Confidence Interval for Mean Min Max Lower Bound Upper Bound single parent 32 60 34 5 637 997 58 31 62 38 48 64 two parent no step parents 42 61 81 3 583 553 60 69 62 93 50 64 two parent with step parent 26 58 77 8 392 1 646 55 38 62 16 28 64 Total 100 60 55 5 880 588 59 38 61 72 28 64 Test of Homogeneity of Variances Loyalty Levene Statistic df1 df2 Sig 5 933 2 97 004 ANOVA Loyalty Sum of Squares Df Mean Square F Sig Between Groups 150 440 2 75 220 2 230 113 Within Groups 3272 310 97 33 735 Total 3422 750 99 Multiple Comparisons Loyalty Tukey HSD (I) Household you grew up in (J) Household you grew up in Mean Difference (I J) Std Error Sig 95 Confidence Interval Lower Bound Upper Bound single parent two parent no step parents 1 466 1 363 532 4 71 1 78 two parent with step parent 1 575 1 534 562 2 08 5 22 two parent no step parents single parent 1 466 1 363 532 1 78 4 71 two parent with step parent 3 040 1 449 096 41 6 49 two parent with step parent single parent 1 575 1 534 562 5 22 2 08 two parent no step parents 3 040 1 449 096 6 49 41 Part 2The APA Write Up Instructions As with previous assignments, the American Psychological Association (APA) has standards for how statistical results should be presented While the actual word choice varies, there are several essential components that are common among all presentations of statistical results and interpretations Use the following instructions for ALL APA write ups required for this course For each analysis, use the following steps to write a complete description of results in proper APA format State what hypothesis was tested State what test was used What decision did you make Reject the null or retain (fail to reject) the null Were the groups significantly different from each other Report the means and standard deviations for each group Put numbers in APA format General Format s ymbol for the test (df) obtained value, p or significance level Specific for F Tests F (2, 99) 3 98, p

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General Instructions: In this assignment, we will be examining 2 One-Way ANOVAs and interpreting the results. As with previous assignments, the Aspelmeier and Pierce text

General Instructions: In this assignment, we will be examining 2 One-Way ANOVAs and interpreting the results. As with previous assignments, the Aspelmeier and Pierce text does a wonderful job of explaining how to actually run the tests in Chapter 8. Follow their instructions for interpreting the SPSS output results I have given you for this assignment.

ANOVA

The researchers want to compare the mean rating of Emotional Support of the groups of where students currently live (1=Dorm, 2=Apartment or House with Peers or Alone, 3=Parents). Also, researchers think that the family composition of the house people grow up in will influence the amount of loyalty females will reported with their closest female friends. As we learned from the text and the PPTs, we know these research situations require the use of the ANOVA. Here are the researchers' hypotheses:

The researchers think that students who live at home will report different levels of emotional support from their closest female friends than those students who live either in the dorms or in an apartment or house with peers or alone.
The researchers also believe that females will report differing levels of loyalty with their closest female friends based on the family composition of the house in which they grew up.

Use the SPSS data to and make conclusions.

Part 1The Analyses

For this assignment, we will need to run 2 One Way ANOVA Tests: one comparing levels of where students currently live and one comparing the family composition of the house in which they grew up. Unlike the last assignment, our groups are already formed.
We also need to run the Tukey multiple comparison procedures.
Additionally, we need to create a graph for each hypothesis.

Hypotheses:

The researchers think that students who live at home will report different levels of emotional support from their closest female friends than those students who live either in the dorms or in an apartment or house with peers or alone.
The researchers also believe that females will report differing levels of loyalty with their closest female friends based on the family composition of the house in which they grew up.

Hypothesis One Output

Descriptives
EmoSupport
	N	Mean	Std. Deviation	Std. Error	95% Confidence Interval for Mean	Min	Max
Lower Bound	Upper Bound
Dorm	34	57.44	7.166	1.229	54.94	59.94	37	64
Apartment or House with Peers or Self	34	56.09	7.012	1.203	53.64	58.53	40	64
Parents	32	55.75	10.479	1.852	51.97	59.53	9	64
Total	100	56.44	8.272	.827	54.80	58.08	9	64

Test of Homogeneity of Variances
EmoSupport
Levene Statistic	df1	df2	Sig.
.191	2	97	.827
ANOVA
EmoSupport
	Sum of Squares	Df	Mean Square	F	Sig.
Between Groups	53.522	2	26.761	.386	.681
Within Groups	6721.118	97	69.290
Total	6774.640	99

Multiple Comparisons
EmoSupport Tukey HSD
(I) Where do you live	(J) Where do you live	Mean Difference (I-J)	Std. Error	Sig.	95% Confidence Interval
Lower Bound	Upper Bound
Dorm	Apartment or House with Peers or Self	1.353	2.019	.781	-3.45	6.16
Parents	1.691	2.050	.689	-3.19	6.57
Apartment or House with Peers or Self	Dorm	-1.353	2.019	.781	-6.16	3.45
Parents	.338	2.050	.985	-4.54	5.22
Parents	Dorm	-1.691	2.050	.689	-6.57	3.19
Apartment or House with Peers or Self	-.338	2.050	.985	-5.22	4.54

Hypothesis Two Output:

Descriptives
Loyalty
	N	Mean	Std. Deviation	Std. Error	95% Confidence Interval for Mean	Min	Max
Lower Bound	Upper Bound
single parent	32	60.34	5.637	.997	58.31	62.38	48	64
two parent no step-parents	42	61.81	3.583	.553	60.69	62.93	50	64
two parent with step-parent	26	58.77	8.392	1.646	55.38	62.16	28	64
Total	100	60.55	5.880	.588	59.38	61.72	28	64
Test of Homogeneity of Variances
Loyalty
Levene Statistic	df1	df2	Sig.
5.933	2	97	.004

ANOVA
Loyalty
	Sum of Squares	Df	Mean Square	F	Sig.
Between Groups	150.440	2	75.220	2.230	.113
Within Groups	3272.310	97	33.735
Total	3422.750	99
Multiple Comparisons
Loyalty Tukey HSD
(I) Household you grew up in	(J) Household you grew up in	Mean Difference (I-J)	Std. Error	Sig.	95% Confidence Interval
Lower Bound	Upper Bound
single parent	two parent no step-parents	-1.466	1.363	.532	-4.71	1.78
two parent with step-parent	1.575	1.534	.562	-2.08	5.22
two parent no step-parents	single parent	1.466	1.363	.532	-1.78	4.71
two parent with step-parent	3.040	1.449	.096	-.41	6.49
two parent with step-parent	single parent	-1.575	1.534	.562	-5.22	2.08
two parent no step-parents	-3.040	1.449	.096	-6.49	.41

Part 2The APA Write-Up Instructions

As with previous assignments, the American Psychological Association (APA) has standards for how statistical results should be presented. While the actual word choice varies, there are several essential components that are common among all presentations of statistical results and interpretations. Use the following instructions for ALL APA write-ups required for this course:

For each analysis, use the following steps to write a complete description of results in proper APA format.

State what hypothesis was tested. -
State what test was used.
What decision did you make? Reject the null or retain (fail to reject) the null.
Were the groups significantly different from each other?
Report the means and standard deviations for each group.
Put numbers in APA format:
1. General Format: symbol for the test(df)= obtained value, p> or < significance level
2. Specific for FTests: F(2, 99)=3.98, p<.05
  1. Now you need to discuss which of the mean comparisons done by the Tukey were significant. You do not need to report numbers just which groups were different from each other, if any.
Report Effect Size (if known)

Example:

Freshmen and Sophmores were expected to score significantly higher on a measure of depression than were Juniors and Seniors. A One-Way ANOVA was used to test the hypothesis leading to the rejection of the null hypothesis, indicating a significant difference between the means, F(3, 96)=4.61, p<.05. Tukey post-hoc tests revealed that Freshmen (M=9.65, SD=1.59) were significantly more depressed than were Juniors (M=4.59, SD=.98) and Seniors (M=5.68, SD=1.22) but not significantly different from Sophomores (M=8.95, SD=1.43). Also, Sophomores were significantly more depressed than Juniors and Seniors but not Freshman.

Since we ran 2 analyses, you will do 2 write-ups for this assignment.

Hypothesis One: The researchers think that students who live at home will report different levels of emotional support from their closest female friends than those students who live either in the dorms or in an apartment or house with peers or alone.

Answer the following questions
1. What is the null hypothesis tested?
2. Can we assume equal variances? (Was the Levene's Test for Equality of Variance significant or not significant?)
3. Write up the results for the ANOVA and the Tukey procedure for Hypothesis One below:

Hypothesis Two: The researchers also believe that females will report differing levels of loyalty with their closest female friends based on the family composition of the house in which they grew up.

Answer the following questions
1. What is the null hypothesis tested?__________________________
2. Can we assume equal variances? (Was the Levene's Test for Equality of Variance significant or not significant?)
3. Write up the results for the ANOVA and the Tukey procedure for Hypothesis One below: