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Generalize your listComp to listComp2 g slist1 slist2 cond = [g x y | x Here g is to be applied to elements in the
Generalize your listComp to listComp2 g slist1 slist2 cond = [g x y | x Here g is to be applied to elements in the Cartesian product of the two lists that satisfy the condition given by cond. Extra credits if you implement listComp2 using listComp.
listComp2 :: (t1 -> t2 -> a) -> [t1] -> [t2] -> (t1 -> t2 -> Bool) -> [a]
here us the listComp (takes 3 inputs : the first is function , the second a list abd the third a predicate, and constructs a list by filtering the input list with the predicate then applying the function to the elements in the resultant list.
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