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Given the following codes for each register in the Basic computer to gain the common bus: AR(001), PC(010), DR(011), AC(100),IR(101),TR(110), Memory(111), IEN (JK). (Answer 6, 7,8,9) [6] The following control statement "If (A=1) then (DR M[AR]) else if (Y=0) then (M[AR] DR)" could be represented as: a) AY: DR-M[AR] b) A:DRM[AR] Y:M[AR]DR AY:M[AR]DR c) A:DRM[AR] d) A : DR M[AR] AY: M[AR] DR AY:M[AR]DR [7] In order to transfer a data from the memory to the DR register, while prohibiting the computer from being interrupted, the following signals should be activated: a) S(011),K=1,read(M),LD(DR) b) S(111),read(M),J=1,LD(DR) c) S(111),K=1,read(M),LD(DR) d) S(011),J=1,read(M),LD(DR) [8] According to the interrupt service, an I/O service routine starts at address location 1000 , The contents of M[0] during the execution of the interrupt was 246 . The contents of PC and M[1] at the beginning of execution are respectively: a) 245,0 BUN 1000 b) 246,0BUN1000 c) 247,0BUN1000 d) 1000,1 BUN 246 [9] Enabling Interrupts and skipping next instruction could be done using the following two commands respectively: a) IEN1,AR4M[AR]+1 b) IEN0,PCPC+1 c) IEN1,PCPC+1 d) IEN40,AR4M[AR]+1